if x and y this find x2+y2
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Hi friend!!
Let given two variables be x and y .
We know that (x+y)²=x²+y²+2xy
→(x+y)²-2xy=x²+y²
So, x²+y²=(x+y)²-2xy ----(1)
And also, (x-y)²=x²+y²-2xy
→(x-y)²+2xy=x²+y²
So, x²+y²=(x-y)²+2xy-----(2)
Adding (1) and (2), we get
2(x²+y²)=(x+y)²+(x-y)²+2xy-2xy
2(x²+y²)=(x+y)²+(x-y)²
x²+y²=[(x+y)²+(x-y)²]/2
I hope this will help u :)
Let given two variables be x and y .
We know that (x+y)²=x²+y²+2xy
→(x+y)²-2xy=x²+y²
So, x²+y²=(x+y)²-2xy ----(1)
And also, (x-y)²=x²+y²-2xy
→(x-y)²+2xy=x²+y²
So, x²+y²=(x-y)²+2xy-----(2)
Adding (1) and (2), we get
2(x²+y²)=(x+y)²+(x-y)²+2xy-2xy
2(x²+y²)=(x+y)²+(x-y)²
x²+y²=[(x+y)²+(x-y)²]/2
I hope this will help u :)
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