Math, asked by aishudiva05, 8 months ago

If x and y varies inversely as each other and x = 8 when y = 32 . FIND Y WHEN X = 16

Answers

Answered by pratiksha2025
11

Step-by-step explanation:

x = 8; 32

y = 16; y2

since it is inverse proportion

therefore, 8×32 ÷ 16 = 16

Attachments:
Answered by pulakmath007
0

The value of y = 16

Given :

  • x and y varies inversely as each other

  • x = 8 when y = 32

To find :

The value of y when x = 16

Solution :

Step 1 of 3 :

Form the equation

Here it is given that x and y varies inversely as each other

 \displaystyle \sf{x \propto \: \frac{1}{y} }

 \displaystyle \sf{ \implies \: x = \: \frac{k}{y} }

 \displaystyle \sf{ \implies \: xy = k } \: \: \: \: - - - (1)

Where k is a non zero real number

Step 2 of 3 :

Find the value of k

 \displaystyle \sf{ \implies \: xy = k } \: \: \: \: - - - (1)

x = 8 when y = 32 gives

 \displaystyle \sf{ \implies \: (8 \times 32) = k }

 \displaystyle \sf{ \implies \: k = 256 }

Equation 1 gives

 \displaystyle \sf{ \implies \: xy = 256}

Step 3 of 3 :

Find value of y when x = 16

 \displaystyle \sf{ \implies \: xy = 256}

For x = 16 we have

 \displaystyle \sf{ \implies \: 16y = 256}

 \displaystyle \sf{ \implies \: y = 16}

Hence the required value of y = 16

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