Question

If x and y vary inversly and x=18 when y=8,find x when y=16

Answer 1

Answer:

Step-by-step explanation:

In inverse proportion:

x1*y1 = x2*y2

18*8 = x*16

So,

18*8 divided by 16 = x

So, 9 = x

Answer 2

The required value of x = 9

Given :

x and y vary inversely and x = 18 when y = 8

To find :

The value of x when y = 16

Solution :

Step 1 of 3 :

Form the equation

x and y vary inversely

$\displaystyle \sf{ \implies x \propto \: \frac{1}{y} }$

$\displaystyle \sf{ \implies x = \: \frac{k}{y} }$

$\displaystyle \sf{ \implies xy = k \: \: \: \: - - - (1)}$

Where k is non zero constant

Step 2 of 3 :

Find the value of k

x = 18 when y = 8

From Equation 1 we get

18 × 8 = k

⇒ k = 144

From Equation 1 we get

$\displaystyle \sf{ xy = 144 \: \: \: \: - - - (2)}$

Step 3 of 3 :

Find the value of x

Putting y = 9 in Equation 2 we get

$\displaystyle \sf{ \implies 9x = 144 \: }$

$\displaystyle \sf{ \implies x = 16 \: }$

The required value of x = 9

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