Question

If x=asec+btan and y= tan+bsec then prove that x²-y²= a²-b²

Answer 1

Answer:

Step-by-step explanation:

x=asecA+btanA ,y=atanA+bsecA

x²-y²=(asecA+btanA)²-(atanA+bsecA)²

=a²sec²A+b²tan²A+2absecAtanA-(a²tan²A+b²tan²A+2absecAtanA)

=a²(sec²A-tan²A)+b²(tan²A-sec²A)+2absecAtanA-2absecAtanA

=a²*1+b²*(1-)

=a²-b²

Hence proved