Math, asked by sabnamsultana69087, 9 months ago

if x=asec theta, y=btan theta then b^2x^2-a^2y^2 is-

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Answered by RishiAEC

Answer:

69 If log3(x cube div by x) -2 log3 3x2 = a-b log3x Find a and b ... that (sin theta-2 sin cube theta)/(2 cos cube theta - cos theta)= tan theta ... 176 red soil iis less fertile give reason.

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if x=asec theta, y=btan theta then b^2x^2-a^2y^2 is-​

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if x=asec theta, y=btan theta then b^2x^2-a^2y^2 is-