if x =Asia theta + B cos theta then xsquare +y square = asquare+ b square
gopika43:
i think ur question is incomplete
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X=a sintheta + bcos theta
To prove = x^2 +y^2 = a^2 + b^2
(a sintheta) ^2 + (b costheta) ^2
a^2sin^2theta + b^2 cos^2theta
a^2+b^2 ( sin^2theta + cos^2theta=1)
Hence proved
To prove = x^2 +y^2 = a^2 + b^2
(a sintheta) ^2 + (b costheta) ^2
a^2sin^2theta + b^2 cos^2theta
a^2+b^2 ( sin^2theta + cos^2theta=1)
Hence proved
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