if x=asin theta and y=acos then find value of x^2+y^2
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a sin square + a cos square theta
= 1
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Given,
x= asin∅ and y=acos∅
To find:x²+y²
Now,
x² = (asin∅)² =a²sin²∅.......................[i]
y² = (acos∅)² = a²cos²∅......................[ii]
Adding [i] and [ii],
x² + y² = a²sin²∅+a²cos²∅
= a²(sin²∅+cos²∅)
»x²+y²=a². [Since,sin²∅+cos²∅=1]
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