If x= asin thita, y = b ten thita ,then
a^2/x^2 - b^2/y^2=?
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Answer:
the answer is 1
Step-by-step explanation:
a²/x² - b²/y² can be written as
a²/(a sin∅)² - b²/(b tan∅)²
then a and b get cancelled
1/sin²∅ - cos²∅/sin²∅
according to identity
1-cos²∅ = sin²∅
sin²∅/sin²∅ = 1
hope this helped u
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