Math, asked by vikashkr88, 1 year ago

If x= asin thita, y = b ten thita ,then
a^2/x^2 - b^2/y^2=?​

Answers

Answered by srinibhasrikanth
1

Answer:

the answer is 1

Step-by-step explanation:

a²/x² - b²/y² can be written as

a²/(a sin∅)² - b²/(b tan∅)²

then a and b get cancelled

1/sin²∅ - cos²∅/sin²∅

according to identity

1-cos²∅ = sin²∅

sin²∅/sin²∅ = 1

hope this helped u

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