Question

If x= at^2+ bt^3+ct
Find dimension of a,b,c X
= displacement
T= time

Answer 1

Answer:

a=[L$T^{-2}$];b=[L$T^{-3}$];c=[L$T^{-1}$]

Explanation:

x=a$t^{2}$+b$t^{3}$+c$t^{1}$

L=[L$T^{-2}$]$T^{2}$+[L$T^{-3}$]$T^{3}$+[L$T^{-1}$]T

a=[L$T^{-2}$];b=[L$T^{-3}$];c=[L$T^{-1}$]