Physics, asked by ankita536895, 1 year ago

If x=at³and y =bt²,find dy÷dx ​


adarsh08: can i know..whats wrong with my answer

Answers

Answered by yashaswini98
6

hey mate,

here is your answer

x=at^3

dx=3at^2

y=bt^2

dy=2bt

dy/dx=2bt/3at^2

=2b/3at

hope it helps you


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Answered by adarsh08
3

Answer:

dy\dx = 2b\3at

Explanation:

Consider,

        x = at^3

 Differentiate with respect to 't' on both sides,

              dx\dt = 3at^2

 Now,

        y = bt^2

 Differentiate with respect to 't' on both sides,

               dy\dt = 2bt

For,  

         dy\dx =  dy\dt divided by dx\dt

                    =  2bt \ 3at^2

                     =  2b \ 3at

Here for differentiating we use the formulae,  d\dx x^n = nx^n-1

Hope..You have got the answer

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