If x=at³and y =bt²,find dy÷dx
adarsh08:
can i know..whats wrong with my answer
Answers
Answered by
6
hey mate,
here is your answer
x=at^3
dx=3at^2
y=bt^2
dy=2bt
dy/dx=2bt/3at^2
=2b/3at
hope it helps you
Answered by
3
Answer:
dy\dx = 2b\3at
Explanation:
Consider,
x = at^3
Differentiate with respect to 't' on both sides,
dx\dt = 3at^2
Now,
y = bt^2
Differentiate with respect to 't' on both sides,
dy\dt = 2bt
For,
dy\dx = dy\dt divided by dx\dt
= 2bt \ 3at^2
= 2b \ 3at
Here for differentiating we use the formulae, d\dx x^n = nx^n-1
Hope..You have got the answer
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