If (x + ax + bx+6) has (x - 2) as a factor and leaves a remainder 3 when
divided by (x - 3), find the values of a and b.
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sᴏʟᴜᴛɪᴏɴ
ʟᴇғᴛ ғ(x) =
x3+ᴀx2+ʙx+6
x-2=0⇒ x=2
sɪɴᴄᴇ, x-2 ɪs ᴀ ғᴀᴄᴛᴏʀ, ʀᴇᴍᴀɪɴᴅᴇʀ=0
∴ ғ(2)=0
(2)3+ᴀ(2)2+ʙ(2)+6=0
8+4ᴀ+2ʙ+6=0
2ᴀ+ʙ+7=0 .........(1)
ᴏɴ ᴅɪᴠɪᴅɪɴɢ ғ(x)ʙʏ x-3, ɪᴛ ʟᴇᴀᴠᴇs ᴀ ʀᴇᴍᴀɪɴᴅᴇʀ 3.
∴ ғ(3)=3
(3)3+ᴀ(3)2+ʙ(3)+6=3
27+9ᴀ+3ʙ+6=3
3ᴀ+ʙ+10 ...........(2)
sᴜʙᴛʀᴀᴄᴛɪɴɢ (1) ғʀᴏᴍ (2), ᴡᴇ ɢᴇᴛ,
ᴀ+3=0
ᴀ=-3
sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴀ ɪɴ (1), ᴡᴇ ɢᴇᴛ,
-6+ʙ+7=0
ʙ=-1
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