Question

if x/(b+a-c)=y/(c+a-b)=z/(a+b-c), then find the value of (b-c)x+(c-a)y+(a-b)z=?​

Answer 1

Step-by-step explanation:

<br> x=k(b+c-a)<br> y=k(c+a-b)<br> z=k(a+b-c)<br> (b-c)x+(c-a)y+(a-b)z<br> =k{(b+c-a)(b-c)+(c+a-b)(c-a)+(a+b-c)(a-b)}<br> =k{b^2-c^2-a(b-c)+c^2-a^2-b(c-a)+a^2-b^2-c(a+b)}<br> =k{a(c-b)+b(a-c)+c(b-a)}<br> =k{0}=0.