If x/(b+c-a) = y/(c+a-b) = z/(a+b-c), show that each ratio is equal to (x+y+z)/(a+b+c)
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x,(b+c-a)=y,(c+a-b)=z,(a+b-c), show that ( b-c)x+(c-a)y+(a-b)z=0. ... check-circle. Text Solution. Solution : Related V
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