Question

if x /(b+c-a)=y/(c+a-b)=z/(a+b-c) then (b-c)x+(c-a)y+(a-b)z is​

Answer 1

Answer:

HEY MATE HERE'S YOUR ANSWER

Step-by-step explanation:

$</p><p>Solution : </p><p></p><p> \frac{ x}{b+c−a}= \frac{y}{c+a−b}= \frac{ z}{a+b−c}=k \: xb+c-a=yc+a-b=za+b-c=k</p><p>x=k(b+c-a)</p><p>y=k(c+a-b)</p><p>z=k(a+b-c)</p><p>(b-c)x+(c-a)y+(a-b)z</p><p>=k{(b+c-a)(b-c)+(c+a-b)(c-a)+(a+b-c)(a-b)}</p><p>=k{b^2-c^2-a(b-c)+c^2-a^2-b(c-a)+a^2-b^2-c(a+b)}</p><p>=k{a(c-b)+b(a-c)+c(b-a)}</p><p>=k{0}=0.</p><p></p><p></p><p>$

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