Question

If x/b+c-a = y/c+a-b = z/a+b-c then, (b-c)x + (c-a)y + (a-b)z is? ​

Answer 1

Step-by-step explanation:

let x/b+c-a = y/c+a-b = z/a+b-c =k

x/b+c-a = k

x=k(b+c-a)

y/c+a-b = =k

y=k(c+a-b)

z/a+b-c=k

z=k(a+b-c)

(b-c)x + (c-a)y + (a-b)z =(b-c)k(b+c-a) + (c-a)kc+a-b) + (a-b)k(a+b-c)

=k(b^2+bc-ba-bc-c^2+ca + c^2+ca-bc-ac-a^2+ab +a^2+ab-ac-ba-b^2+-bc)

= k(0)

=0