Question

If x/(b-c) = y/(c-a) = z/(a-b), Prove that: ax+by+cz = 0

Answer 1

Answer-

Given, x/(b-c) = y/(c-a) = z/(a-b) k(say)

Answer 2

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Step-by-step explanation:

x=k(b-c) , y=k(c-a) , z=k(a-b)

ax+by+cz

=ak(b-c)+bk(c-a)+ck(a-b)

= abk-ack+bck-abk+ack-bck (cut the common factors)

=0

LHS=RHS

hence proved