Question

if x/b + c =y/ c + a =z/ a + b show that (b – c) x + (c – a) y + (a – b) z = 0

Answer 1

Answer

x/b+c=y/c+a=z/a+b=k(let)

then

x=k(b+c)

y=k(c+a)

z=k(a+b)

(b-c)k(b+c) + (c-a)k(c+a) + (a-b)k(a+b)

=k[b^2-c^2+c^2-a^2+a^2-b^2]

=k(0)

=0