Question

If
x/b+c = y/c+a = z/a+b
show that (b-c) x + (c-a) y + (a - b) z = 0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

let x/b+c= y/c+a = z/a+b =k

therefore x = (b+c)k, y= (c+a)k & z = (a+b)k

acc. to the qs by putting all the value of x, y, z we get the result = 0