Question

if x/b-c=y/c-a=z/a-b then show that ax+by+cy=0
please give me the answer as I have exams ​

Answer 1

Answer:

Given, x/b-c=y/c-a=z/a-b=m(say)

then x=m(b-c)

y=m(c-a)

z=m(a-b)

now

L.HS= ax+by+cy

=am(b-c)+bm(c-a)+cm(a-b)

=amb-amc+bmc-bma+cma-cmb

=0

=R.HS