Math, asked by nitin6071, 10 months ago

If x be real then 2x^2+5x-3>0 if
A)x<-2
B)x>0
C)x>1
D)none of these

Answers

Answered by sswaraj04
2

Answer:

c)

Step-by-step explanation:

2x^2+5x-3>0

x^2+5x/2-3/2>0

x^2+3x-x/2-3/2>0

x(x+3) -1/2(x+3)>0

(x+3)(x-1/2)>0

x: (-inf,-3) U (1/2 inf)

as per option

C) x>1  fits in given range

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