If x be the A.M. between y and z, y the G.M. between z and x, prove that z be the H.M. between x and y.
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Answer:
x=(y+z)/2.....eqn i
y^2=xz
now,
multiplying by y in eqn i
so, xy=(y^2+zy)/2
2xy= xz+zy (y^2=xz)
2xy= z(x+y) taking z common
z = 2xy/(x+y)
proved
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