Question

If x beakers of 100 ml containing 1 : 4 acid-water solution are mixed with y beakers of 200 ml containing 3 : 17 acid-water solution then the ratio of acid to water in the resulting mixture becomes 19 : 91. Find x : y.

Answer 1

x beakers of 100 ml containing 1 : 4 acid-water solution are mixed with y beakers of 200 ml containing 3 : 17 acid-water solution then the ratio of acid to water in the resulting mixture becomes 19 : 91. Find x : y.

Answer 2

Answer:

The ratio of x : y is 5:3.

Explanation:

In x beakers of 100 ml containing 1 : 4 acid-water solution.

Volume of acid = $\frac{100 x}{5}=20x$

Volume of water =  $\frac{400 x}{5}=80x$

In y beakers of 200 ml containing 3 : 17 acid-water solution:

Volume of acid =  $\frac{600 y}{20}=30y$

Volume of water = $\frac{3400 y}{20}=170y$

On mixing the ratio of acid to water is 19:91.

$\frac{20x+30y}{80x+170y}=\frac{19}{91}$

$\frac{x}{y}=\frac{5}{3}$

The ratio of x : y is 5:3.