Question

If x belongs to whole numbers, then solution set of x<2 is?​

Answer 1

Answer:  

Consider the first inequality

2(x−1)<3x−1

2x−2<3x−1

−1<x ...(i)

Consider the second inequality

4x−3≤8+x

3x≤11

x≤  

3

11

​  

 

x≤  

3

9+2

​  

 

x≤3+  

3

2

​  

 but x is an integer

Hence, we neglect the fractional part of x.  

3

2

​  

<1, therefore

x≤3 ...(ii)

From (i) and (ii), we have

−1<x≤3

x∈(−1,3] (−1 is not included)

So, the solution set for the above inequalities is {0,1,2,3}

Step-by-step explanation: