Question

If x = bt + ct², find the dimensions of b and c,where x is length and t is time.

Answer 1

Answer:

dimensions of b and c are [LT^-1] and [LT^-2]

Explanation:

By principle of homogeineity, we get,

[x] = [bt]

=> [L] = [b] × [T]

=> [b] = [L] / [T]

= [LT^-1]

similarly,

[x] = [ct^2]

=> [L] = [c][T^2]

=> [c] = [LT^-2]

Answer 2

Answer:

Here is your answer hope you understand