if x cos theta is equal to 1 and tan theta is equal to y , find the value of x square minus y square
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The value of x²-y² = 1.
- Given :
x cosθ = 1 and tanθ = y
x = 1/cosθ
x = secθ (Equation 1)
AND
tanθ = y
- Now we have to find the value of x²-y²,
- Substituting the value of x and y from the result obtained,
x²-y² = (secθ)² - (tanθ)²
= sec²θ - tan²θ
- We know the identity sec²θ - tan²θ =1
∴ x²-y² = 1
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