If x = cos theta + sin theta, y = cos theta sin then, then
a) x^2 = 1 + 2y
b) x^2 + 2y = 1
c) x^2 + 1 = 2y
d) x^2 - 2y = 0
This is sooo hard omg
Can you pls help me
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Answers
Answered by
2
Answer:
Answer
x = a(θ − sinθ) & y = a(1 + cosθ)
Now,
dθ
dx
=a(1−cosθ) &
dθ
dy
=a(−sinθ).
∴
dx
dy
=−
(1−cosθ)
sinθ
=−
2sin
2
2
θ
2sin
2
θ
cos
2
θ
=−
2sin
2
θ
2cos
2
θ
=−cot
2
θ
Now,
dx
2
d
2
y
=
2
1
cosec
2
(
2
θ
)
dx
dθ
=
2
1
cosec
2
(
2
θ
)
2asin
2
2
θ
1
=
4asin
4
2
θ
1
=
4a(1−
2a
y
)
2
1
[Since,y=2acos
2
2
θ
⇒sin
2
2
θ
=(1−
2a
y
)]
Step-by-step explanation:
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Answered by
1
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12th
>Maths
>Continuity and Differentiability
>Second Order Derivatives
>If x = costheta ,y = sin5th...
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If x=cosθ,y=sin5θ then (1−x
2
)
dx
2
d
2
y
−x
dx
dy
=
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D
−25y
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