Question

If x cos y + y sin x +1, then find dy

.

dx​

Answer 1

Answer:

On differentiating the expression with respect to x, we get :

x (-siny)dy/dx + cosy(1) + sinx(dy/dx) + y(cosx) + 0 = 0

(We have applied the product rule here)

cosy + ycosx = xsinydy/dx - sinxdy/dx

Taking dy/dx common,

cosy + ycosx = dy/dx (xsiny - sinx)

Or, dy/dx = (Cosy + ycosx) / (xsiny - sinx)

This is your required answer.