Question

If x cosec2 30 degree sec2 45 degree by 8 cos2 45 degree sin2 60 degree = tan2 60 degree - tan2 30 degree, find x

Answer 1

Answer:

$\frac{x { (csc30) }^{2} { (sec45) }^{2} }{8 { (cos45) }^{2} { (sin60) }^{2} } = { (tan60) }^{2} - { (tan30) }^{2}$

$\frac{x \times 4 \times 2 \times 2 \times 4}{8 \times3 } = \frac{1}{3} \times 3 \\ \times = \frac{3}{8}$

hope it help you dear ✌️✌️✌️✌️