If x=cosecA +cosA and y = cosec A - cosA then prove that (2/x+y)square + (x-y/2)square - 1 =0
Answers
Answered by
138
x = cosec A + cos A y = cosec A - cos A
=> x+y = 2 cosec A
=> 2/(x+y) = sinA
(x - y)/2 = cos A
LHS = [ 2/(x+y) ]² + [(x-y)/2]² - 1
= sin² A + cos ² A - 1
= 1 - 1 = 0
=> x+y = 2 cosec A
=> 2/(x+y) = sinA
(x - y)/2 = cos A
LHS = [ 2/(x+y) ]² + [(x-y)/2]² - 1
= sin² A + cos ² A - 1
= 1 - 1 = 0
kvnmurty:
clik on thanks. selct best ans
Answered by
82
ANSWER IS IN THE ATTACHMENT
Attachments:
Similar questions
English,
8 months ago
Computer Science,
8 months ago
Physics,
1 year ago
Social Sciences,
1 year ago
Economy,
1 year ago
Math,
1 year ago