if x cube + 1 upon x cube is equal to 110 and what is the value of x plus one upon x
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x^3 + 1/x^3 = ( x + 1/x ) ( x^2 - 1 + 1/x^2 )
= (x + 1/x ) { (x + 1/x)^2 - 3}
put x+ 1/x = a
110 = a ( a^2 -3)
after that try and fail method we can use ...
you can put 0,1,2 ....values
here , we can use factors of 110
110= 2×5×11 = a × (a^2 -3)
means , a would be 2 or 5 or 11
put this values in equation
you can find a=5 is correct
this method is better for bigger values
= (x + 1/x ) { (x + 1/x)^2 - 3}
put x+ 1/x = a
110 = a ( a^2 -3)
after that try and fail method we can use ...
you can put 0,1,2 ....values
here , we can use factors of 110
110= 2×5×11 = a × (a^2 -3)
means , a would be 2 or 5 or 11
put this values in equation
you can find a=5 is correct
this method is better for bigger values
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