Math, asked by suvasishbhattacharji, 9 months ago

If x cube - 3b square + 2c cube is divisible by (x-a) and (x-b). Find the value of a+b+c when a, b & c are real and a not equal to b. ​

Answers

Answered by aatifnasir2009
2

Answer:

If A : B = 7 : 9 and B : C = 6 : 7 then A : C is (a) 2 : 3 (b) 3 : 2 (c) 1 : 3 ... (xa–b)a+b× (xb–c)b+ c× (xc–a)c+a where x 1 0 and (a) 0 (b) 1 (c) 2 (d) 3 If x = 2+ 2 and y = 2-2, then find the value of(x2+y2). (a) 12 (b) ... 57 3 4 sq.cm (b) (c) 6 cm2 (d) 12cm2 The square of a natural number when subtracted from its cube results in 48

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