Question

if x cube - 3x square +4x+k divided by (x-2)​

Answer 1

Step-by-step explanation:

$({x}^{3} - 3x ^{2} + 4x + k) \div (x - 2) \\ = {x}^{2} (x - 2) - x + 4x + k$

$= {x}^{2} (x - 2) - 1(x - 2) - 2 + 4x + k$

$= {x}^{2} (x - 2) - 1(x - 2) + 4x + k \\ = {x}^{2} ( x - 2) - 1(x - 2)+ 4(x - 2) - 8 + k \\ = ({x}^{2} - 1 + 4) \times (x - 2) + ( - 8 + k)$

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