If x cube+9xsquare+bx+6 has (x-2) as a factor and leaves a remainder 3, when divided by x -3, then find the values of a and b
Answers
Answered by
1
x-2=0
x=2
(2)^3+9(2)^2+b(2)+6
x=2
(2)^3+9(2)^2+b(2)+6
Diyaa08:
i think it was not 9, it was ax^3
ax^2 sorry
Answered by
1
HOPE IT HELPS BUDDY!!!
Attachments:
Thanks
welcome
Similar questions