Math, asked by vibhamahajan1783, 1 year ago

If x cube is equal to 1728 and y cube is equal to 5832 find the value of x + 1 upon y

Answers

Answered by arjavjainjain99
0

Answer:

∛1728 = 12

∛5832 = 18

=(x + 1)/y

= (12 + 1)/18

= 13/18

Answered by swati1212
1

Answer:

13/18

Step-by-step explanation:

 {x}^{3}  = 1728

 {y}^{3}  = 5832

so from here X = 12

and Y = 18

the ques is== X+1 / Y

so, 12+1/18= 13/18

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