Math, asked by ayyalurubharathidevi, 6 months ago

if x cube minus 16 x square plus 65 x-50 is equal to x minus a into x minus b into x minus 3 then a + b + c is equal to​

Answers

Answered by s1271
1

Answer:

qual to the sum (or difference) of coefficients of the two like terms. 15-04-2018 ... When we add (or subtract) two algebraic expressions, the like terms are added (or ... The coefficient of xy in 3x2 zy + 7xyz – 2z2x is. (a) 3z. (b) – 2. (c) 7yz. (d) 7z ... you could say: either “x divided by 3” or “one third of x.” 15-04- .Step-by-step explanation:

qual to the sum (or difference) of coefficients of the two like terms. 15-04-2018 ... When we add (or subtract) two algebraic expressions, the like terms are added (or ... The coefficient of xy in 3x2 zy + 7xyz – 2z2x is. (a) 3z. (b) – 2. (c) 7yz. (d) 7z ... you could say: either “x divided by 3” or “one third of x.” 15-04- .

Answered by BrainlyBoomerang
6

SOLUTION:

 {x}^{3}  - 16 {x}^{2}  + 65x - 50 = (x - a)(x - b)(x - c) \\  \\  \\  \\  {x}^{3}  - 16 {x}^{2}  + 65x - 50 = ( {x}^{2}  - (a + b)x + ab)(x - c) \\  \\  \\  \\  {x}^{3}  - 16 {x}^{2}  + 65x - 50 =  {x}^{3}  - (a + b) {x}^{2}  + abx - c{x}^{2}  + c(a + b)x - ab c\\  \\  \\  \\  - 16 {x}^{2}  + 65x - 50 =  - (a + b + c) {x}^{2}  + abx + c(a + b)x - abc \\  \\  \\  \\ 16 {x }^{2}  - 65x + 50 = (a + b + c) {x}^{2}  - abx - c(a + b)x + abc \\  \\  \\  \\ (a + b + c) {x}^{2}  = 16 {x}^{2}  - 65x + 50 + abx - c(a + b)x + abc \\  \\  \\  \\ { \large{ \green{ \boxed{ \red{a + b + c =  \frac{16 {x}^{2} - 65x + 50 + abx - acx - bcx + abc }{ {x}^{2} } }}}}}

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