if x cube minus 2 X square + kx + 5 is divided by x minus 2 and the remainder is 11 find k
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x³-2x²+kx+5 is divided by ( x-2)
x-2=0
x=2
Therefore,
2³-2(2)²+k2+5=11
8-8+2k+5=11
2k+5=11
2k=11-5
2k= 6
k=6
------
2
k=3
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