Question

if x cube minus 6 X square + 6 X + K is completely divisible by x minus 3 and also find the value of k

Answer 1

Let p(x) = x³-6x²+6x+k

And g(x) = x-3

It is given that p(x) is completely divisible by g(x)

=> g(x) is a factor of p(x)

Using factor theorem which states as, if p(a) is a factor of g(x) then g(a)=0

g(x) = x-3

x= 3

p(3) = 0

(3)³-6(3)²+6(3)+k = 0

27-54+18+k = 0

-9+k =0

k is 9

Answer 2

Ur Answer is k=9..?.