if x cube + x square - 2 x minus 3 equal to x minus 2 X square + a x + b + 5 then find the values of a and b by using concept of equality of polynomials
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Answer: x cube + x square - 2 x - 3 is equals to x -2 in multiply X square + a x + b + 5 divisible LHS (X - 2)
Step-by-step explanation: X-2√x cube + x square - 2x - 3
Qutant - X square+3x+4
Remainder- 5
Therefore- (x - 2) (x square + 3 X + 4 ) +5 =(x-2) (x square + a x + b)+5
Comparing both sides,we have a=3 ,b=4
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