If x=e^n-e^-n/e^n+e^-n then the value of n is
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so n=1/2.log(1+x)/1-x
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goutamburnwal1pb6s7w:
dekh de bhai
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Answer:
n = 1/2 log 1+x / 1-x
Step-by-step explanation:
Properties Used
- a^-p = 1/a^p
- log a^p = p log a
- log_e e = 1
- log_e means log to the base e
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