Question

if X equal to 2 + root 3 find the value of x square + 1 by x square​

Answer 1

Answer:

$given \: equation = x = 2 + \sqrt{3} \\ {x}^{2} + 1 {x}^{2} \\ = ({2 + \sqrt{3} })^{2} + 1({2 + \sqrt{3} })^{2} \\ {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ = 4 + 3 + 4 \sqrt{3} + 4 + 3 + 4 \sqrt{3} \\ = 14 + 8 \sqrt{3}$

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