If X equal to 3 + 4 iota then the value of 204 X - 70 X square + 12 x the power cube minus x to the power 4 is
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Step-by-step explanation:
Considering that a,b,cϵR, hence a quadratic equation with real coefficients containing one of its root as complex number, will have the other root as its complex conjugate.
Therefore, in the above case one root is 3−4i.
Therefore other root will be 3+4i.
Hence
a
−b
=3+4i+3−4i
Hence b=−6a...(i)
And
a
c
=(3+4i)(3−4i)
c=25a ...(ii)
Therefore the equation transforms to
ax
2
−6ax+25a=0
Or
x
2
−6x+25=0
Comparing with
ax
2
+bx+c=0 gives us
a=1 b=−6,c=25
Hence
31a+b+c
=31(1)−6+25
=31+25−6
=50
=2(25)
=2c
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