if X equal to 3 is 1 roots of the quadratic equation X square + 2 k r - 6 equal to zero then find the value of k
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x=3(given)
p(x)=x^2 +2kx -6
p(3)=(3)^2 + 2k(3) - 6 =0
9 + 6k = 6
6k=-3
k=-1/2
p(x)=x^2 +2kx -6
p(3)=(3)^2 + 2k(3) - 6 =0
9 + 6k = 6
6k=-3
k=-1/2
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