if X equal to 3 is one zero of the quadratic polynomial x2- 2kx-6 ,then find the value of k
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Answer:
If X =3
then by putting the value of x , we get
3*2-2*k*3-6
=6*(-6)k -6
= -36k
Now
It is given that,
x=3 is the zero of the given polynomials
So,
-36k-6=0
or, -36k= 0+6(transposing-6 to RHS)
or, -36 k = 6
or,-k = -6/36
or,k= 1/6
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