Question

if X equal to 7 + 4 root 3 and x y equal to 1 then what will win the amount of 1 by X square + 1 by 1 square

Answer 1

ans
$97 \times 1 \div 97$

Answer 2

According to the question,
We are given that,
1) x= 7+4√3
2) x*y= 1,

So, We have to find 1/x²+1/y²,
We know that, Since x*y=1, therefore,
y=1/x, therefore y= 1/7+4√3.

Now, we get to put values in the question,
So,
1/x²+1/y²
=> (Now follow me,)
(AFTER THAT PHOTO CONTINUING)
So by rationalising,
1/97+56√3
=> 1/97+56√3 × (97-56√3 ÷ 97-56√3)
=> 97-56√3 ÷ (97)²- (56√3)²
=> 97-56√3 ÷ (9409) - (9408)
=> 97-56√3 ÷ 1

.•. ANS=> 97-56√3

{ Thanks for question, Keep questioning all time and be frank to write them, Stay happy & Stay tuned}

Regards,
Mukul Shrivastava