if X equal to cos power 3 theta equal to b sin power 3 theta then
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hey mate
X=acos³Q
y=bsin³Q
(X/a)^2/3+(y/b)^2/3
put value X and y in eq.
(acos³Q/a)^2/3+(bsin³Q/b)^2/3
(cosQ)^3×2/3 + (sinQ)^3×2/3
cos²Q+Sin²Q
=1
hope it's helpful you
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