if X equal to R sin a into cos b, y equal to R sin a into Sin B, Z equal to R Cos A then X square + Y square + Z square equal to R square
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• Given ;
⋆ X = R.sinA.cosB —( ! )
⋆ Y = R.sinA.sinB —( !! )
⋆ Z = R.cosA —( !!! )
• To Prove ;
⋆ X² + Y² + Z² = R²
• Proof ;
- Adding (!) , (!!) and (!!!)
» X + Y + Z = R.sinA.cosB + R.sinA.sinB + R.cosA
- Squaring Each Term
» X² + Y² + Z² = R².sin²A.cos²B + R².sin²A.sin²B + R².cos²A
» X² + Y² + Z² = R².sin²A(cos²B + sin²B) + R².cos²A
- (cos²B + sin²B = 1)
» X² + Y² + Z² = R².sin²A × 1 + R².cos²A
» X² + Y² + Z² = R².sin²A + R².cos²A
» X² + Y² + Z² = R²(sin²A + cos²A)
- (sin²A + cos²A = 1)
» X² + Y² + Z² = R² × 1
» X² + Y² + Z² = R² Hence, Proved
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