Question

if X equal to root 3 + root 2 then find the value of x squared plus one by x square

Answer 1

x=√3+√2
Therefore,
x^2+1/x^2=
(√3+√2)^2 + 1 /(√3+√2)^2
= 3+2+2√6 +1/3+2+2√6
=6+2√6/ 5+2√6 • 5-2√6/ 5-2√6
= (2√6)^2+(6+5)2√6+6x5/(5)^2-(2√6)^2
=24+22√6+30/25-24
=54+22√6 (Required answer)
Cheers!!
With love,
Harsh