if x equals to 1 by 3 and y equals to 6 by 7 then xy minus y by x equals to ?
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\begin{lgathered}x = \frac{1}{3} \: \: and \: y = \frac{6}{7} \\ \\ xy - \frac{y}{x} \\ \\ \frac{1}{3} \times \frac{6}{7} - \frac{ \frac{6}{7} }{ \frac{1}{3} } \\ \\ \frac{2}{7} - \frac{6}{7} \times \frac{3}{1} \\ \\ \frac{2}{7} - \frac{18}{7} = \frac{ - 16}{7}\end{lgathered}
x=
3
1
andy=
7
6
xy−
x
y
3
1
×
7
6
−
3
1
7
6
7
2
−
7
6
×
1
3
7
2
−
7
18
=
7
−16
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