Question

If X equals to 5 minus 2 root 6, find the value of x square + 1 by x square

Answer 1

Answer:

$x = 5 - 2 \sqrt{6} \\ \\ = > \frac{ {x}^{2} + 1 }{ {x}^{2} } \\ \\ = > \frac{( {5 - 2 \sqrt{6} })^{2} + 1}{( {5 - 2 \sqrt{6} })^{2} } \: \: \\ \\ = > \frac{ {(5)}^{2} + {(2 \sqrt{6)} }^{2} - 2 \times 5 \times 2 \sqrt{6} + 1 }{ {5}^{2} + ( {2 \sqrt{6)} }^{2} - 2 \times 5 \times 2 \sqrt{6} } \\ \\ = > \frac{25 + 24 - 20 \sqrt{6 } + 1}{25 + 24 - 20\sqrt{6 } } \\ \\ = > \frac{50 - 20 \sqrt{6} }{49-20\sqrt{6 } } \: \: \: \: ans</p><p> </p><p>$

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