Question

if X equals to 6 + root 35 find the value of x + 1/X ​

Answer 1

$\begin{gathered}x = 6 - \sqrt{35} \\ \frac{1}{x} = \frac{1}{6 - \sqrt{35} } \\ = \frac{6 + \sqrt{35} }{(6 - \sqrt{35})(6 + \sqrt{35} ) } = \frac{6 + \sqrt{35} }{36 - 35} = 6 + \sqrt{35} \\ {x}^{2} + \frac{1}{ {x}^{2} } = {(6 - \sqrt{35} )}^{2} + {(6 + \sqrt{35} )}^{2} \\ = 36 + 35 - 12 \sqrt{35} + 36 + 35 + 12 \sqrt{35} \\ = 71 + 71 = 142\end{gathered}$

Answer 2

Answer:

Step-by-step explanation: